Math, asked by raghvendraprakash42, 1 month ago

A boy spends 3/4 of his pocket money and then 4/5 of the remainder is given to his sister. If he has rupees 40 left, what did he have at first.

Answers

Answered by pritybanerjee709
1

Step-by-step explanation:

A boy spends 3/4 of his pocket money , that means 1/4 is left

4/5 of the remainder is given to sister

he has Rs40 left

total money as remainder=5/5

money left from remainder after giving to sister=5/5-4/5=1/5

1/5=Rs 40

then , 5/5=40 x 5 =Rs 200

therefore total money as remainder before givinf to sister = Rs 200

3/4 of pocket money spent , then left is 1/4

as we know remainder money was Rs 200 so 1/4 =Rs200

Hope it's helps you

then 3/4 = 200 x 3 =Rs600

total money at the begining or total pocket money before spending=money spent + money left

Rs600+Rs200= Rs 800

therefore the boy had Rs 800 at first

Answered by samir9557
1

Answer

800

Step-by-step explanation:

Let pocket money be = x

x-3/4x is amount remaining with him after spending money

x-3/4x=x/4(on solving)

now he gave 4/5 of remaining about to his sister

= x/4 - 4/5 of x/4

=x/4 - x/5

=x/20

amount remaining with him is = 40

x/20 = 40

x = 800

poket money = 800

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