Question

A boy standing 12 m from a building can just barely reach the roof 10 m above him when he throws a ball at
the optimum angle with respect to the ground. Find the initial velocity components of the ball.

Answer 1

$\red{Hello}$

h = u^2 sin^2 x°/2g

12 = u^2 sin^2 x° /20

(u sin x°)^2 = 240

u sin x° = 4√15

R/2 = 2UxUy/2g

100 = Ux Uy

Ux = 100/4√15

= 25/√15

initial velocity of the ball is =

= Ux i^ + Uyj^

= 25/√15 i^ + 4/√15 j^

Answer 2

Answer:

i don'tknow hehe just joking

Explanation:

h = u^2 sin^2 x°/2g

12 = u^2 sin^2 x° /20

(u sin x°)^2 = 240

u sin x° = 4√15

R/2 = 2UxUy/2g

100 = Ux Uy

Ux = 100/4√15

= 25/√15

initial velocity of the ball is =

= Ux i^ + Uyj^

= 25/√15 i^ + 4/√15 j^