A boy standing 20m away from a wll throws a ball so as to just cross a window at a height 15m from the ground . Find the velocity of projection of the ball
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Answer:
velocity is 20/√3 m/s
for y_axis
s=ut+1/2gt2 u=0 a=-g
15=-5t2
t=√3
for x-axis
s=ut+1/2at2 a=0
20=ut
20=u(√3)
u=20/√3m/s
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