A boy standing at a distance of 15m from the bottom of the tower looks the top of the tower at an angle of elevation 30°.Find the height of the tower.draw the figure
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Given that,
BC = 15m
AB = ?
∠B = 30 degree
we know,
AB/BC = tan 30°
AB/15m = 1/√3
√3×AB = 1×15m
AB = 15m/√3
AB = 3×5/√3
AB = √3×√3×5/√3 ( 3 can be written as √3×√3 = (√3)^2 = 3)
AB = 5√3m
Therefore, the height of the tower is 5√3m.
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