A boy standing at a distance of 72m from a building, observes the top of the building makes an angle of elevation 60°. find the height of the building.
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Here BC is the building and the person is standing at A such that
AB = 72m. In ΔABC, tan300 = BC/AB
Height And Distances Solved
→ √3 = BC/AB → BC=72√3 m
Hence the height of the building is 72√3m.
AB = 72m. In ΔABC, tan300 = BC/AB
Height And Distances Solved
→ √3 = BC/AB → BC=72√3 m
Hence the height of the building is 72√3m.
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ay5497368p821h9:
AB is not 32m
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