A boy standing at the top of tower 20 metre height drop a stone
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Hey Dear,
# Complete question -
Q. A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m/s², the velocity with which it hits the ground is ?
◆ Answer -
v = 20 m/s
◆ Explaination -
# Given -
h = 20 m
g = 10 m/s^2
u = 0 m/s
# Solution -
When a stone is dropped from tower -
v^2 = u^2 + 2g.h
v^2 = 0^2 + 2×10×20
v^2 = 400
v = √400
v = 20 m/s
Hence, the stone hits ground with velocity of 20 m/s.
Thanks dear.
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