Physics, asked by Anonymous, 2 months ago

A boy standing on the fifth floor of a
building drops a soft toy which lands on
the ground with a velocity of 20 m/s.
What would be the time taken by the
toy to reach the ground?
Correct answers only
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Answers

Answered by dapushree
3

Answer:

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Explanation:

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Answered by sujitkundu2709
2

Answer:

Answer:

Answer:Speed : 20 m/sec

Answer:Speed : 20 m/sec Distance : 5 floor = 20/5 = 4.

Answer:Speed : 20 m/sec Distance : 5 floor = 20/5 = 4. Distance : 4

Answer:Speed : 20 m/sec Distance : 5 floor = 20/5 = 4. Distance : 4 Time taken : Distance/Speed

Answer:Speed : 20 m/sec Distance : 5 floor = 20/5 = 4. Distance : 4 Time taken : Distance/Speed : 20/4

Answer:Speed : 20 m/sec Distance : 5 floor = 20/5 = 4. Distance : 4 Time taken : Distance/Speed : 20/4 : 5 sec .

Answer:Speed : 20 m/sec Distance : 5 floor = 20/5 = 4. Distance : 4 Time taken : Distance/Speed : 20/4 : 5 sec . So your answer is 5 sec

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