Question

A boy standing on the ground a flying a kite with a string of length 150 m at an angle of elevation 30 degree and a boy standing on the roof of 25m shipbuilding everything is right at an angle of elevation of 45 degree boys are on opposite sides of the kite find the length of the string to date

Answer 1

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Answer 2

given the length of the string of first kite, AB=150m. Height of the building where the second boy is flying the kite ,CD=EF=25m. BC is the length of the string of second kite such that both the kites meet at B . IN right angles triangle AEB, sin30°=(BE÷150). BE=150×(1÷2)=75m. From the figureBF =BE-EF=75-25 =50m. consider ,the right angled triangle BFC sin45°=(BF÷BC)=(1÷root2)=(50÷BC).therefore ,BC=50root2. Thus the length of string required by the second boy such that the both kites meet is 50÷root2m.