Question

A boy standing on the top of a tower 36 m high has a throw a packet to his friend standing on the ground 48 m horizontally away. If the throws a packet directly aiming the friend with a speed of 10 ms^(-1), how short will be packet fall ?

Answer 1

Answer:

the packet will 46 m before the target

and if theta value is given it will be easy to calculate the answer and also refer the answer for surety of answer

Explanation:

^ indicates the power

@ indicates the theta

by calculation ,

sin@ = opp/ hyp = 3/11

tan @ = 36/48 = 3/✓2

therefore , @ =

range = u ^ 2 sin2@ / 2g

r = 10^2 × 2 (3/11) / 2 ×9.8

r = 2.782 m

I HOPE THIS WILL HELP YOU AND MARK IT AS BRAINLIEST ANSWER