A boy standing on the top of a tower 36 m high has a throw a packet to his friend standing on the ground 48 m horizontally away. If the throws a packet directly aiming the friend with a speed of 10 ms^(-1), how short will be packet fall ?
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Answer:
the packet will 46 m before the target
and if theta value is given it will be easy to calculate the answer and also refer the answer for surety of answer
Explanation:
^ indicates the power
@ indicates the theta
by calculation ,
sin@ = opp/ hyp = 3/11
tan @ = 36/48 = 3/✓2
therefore , @ =
range = u ^ 2 sin2@ / 2g
r = 10^2 × 2 (3/11) / 2 ×9.8
r = 2.782 m
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