Physics, asked by ashwindatta9217, 7 months ago

A boy stands in between two parallel cliffs and explodes a cracker. He hears the first echo after 0.5s and second echo 1.8s after listening to the first echo. Calculate the distance between the cliffs if speed of sound in air is 356 m s-1

Answers

Answered by pujasinghsvrps
0

Answer:

I didn't understand the question so I can't tell you

Answered by knjroopa
0

Explanation:

Given A boy stands in between two parallel cliffs and explodes a cracker. He hears the first echo after 0.5 s and second echo 1.8 s after listening to the first echo. Calculate the distance between the cliffs if speed of sound in air is 356 m s-1

  • Given a boy stands in between two parallel cliffs and bursts a cracker.
  • So let P and Q be the two cliffs at a distance d1 and d2 meter from the boy.
  • Given for d1, v = 356 m/s, t = 0.5 s
  • So for d2, v = 356 m/s, t = 1.8 s
  • So we have d1 = v x t / 2
  •                        = 356 x 0.5 / 2
  •                        = 178 / 2
  •                          = 89 m
  • Also we have d2 = v x t / 2
  •                           = 356 x 1.8 / 2
  •                           = 640.8 / 2
  •                            = 320.4
  • So distance PQ = d1 + d2
  •                         = 89 + 320.4
  •                         = 409.4 m

Reference link will be

brainly.in/question/1468067

brainly.in/question/1743681

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