Question

a boy stands on the edge of a cliff and throwsa stone vertically downward with an initial speed of 10 m/s the instant before the stone hits the ground below it has 1000J of kinetic energy if he were to throw the stone horizontally outward from the Cliff with the same initial speed of 10 m/ s, how much kinetic energy would it have just before it hits the ground​

Answer 1

The K.E of the stone before it hits the ground is 1000 J.

Explanation:

Kinetic Energy at the time of hitting the ground= Potential energy at the edge of cliff + Initial Kinetic energy

when the stone is thrown vertically downward

K 1  =  m g h + 1 /2 m v ^2

     =  1000 J    -------(1)

Now when the stone is thrown horizontally outward with the same speed

K 2  =  m g h + 1/ 2 m v ^2

From equation

K 2  =  1000 J

Thus the K.E of the stone before it hits the ground is 1000 J.

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Answer 2

Answer:

KINETIC ENERGY : 1000 joule