Physics, asked by galipallisoumya, 11 hours ago

a boy starting from rest runs with a uniform acceleration for 5 sec such that he covers a distance of 37.5m in 5 sec calculate the acceleration of the boy and final velocity of the body​

Answers

Answered by Yuseong
10

Answer:

a = 3 m/s²

v = 15 m/s

Explanation:

As per the provided information in the given question, we have :

  • Initial velocity (u) = 0 m/s [Starts from rest]
  • Time taken (t) = 5 seconds
  • Distance (s) = 37.5 m

We've been asked to calculate the acceleration and the final velocity of the body.

Acceleration is defined as the rate of change in velocity. Its SI unit is m/s². It is a vector quantity. We can find the acceleration using the second equation of motion. By using the second equation of motion:

  \longrightarrow \sf{\quad { s = ut + \dfrac{1}{2}at^2}} \\

  • s denotes distance
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

Substitute the values.

  \longrightarrow \sf{\quad { 37.5 = 0(5) + \dfrac{1}{2}\times a \times (5)^2}} \\

  \longrightarrow \sf{\quad { 37.5 = \dfrac{1}{2}\times a \times 25}} \\

  \longrightarrow \sf{\quad { 37.5 \times 2= 1 \times a \times 25}} \\

  \longrightarrow \sf{\quad { 75= 25a}} \\

  \longrightarrow \sf{\quad { \cancel{\dfrac{75}{25}}= a}} \\

  \longrightarrow \quad\underline{\boxed {\pmb{\frak{3 \; m \: s}}^{\pmb{\frak{-2}}}=\pmb{\frak{ a}}}} \\

Therefore, acceleration is 3 m/s².

Now, we have to find the final velocity of the body. In order to find that so, we'll use the first equation of motion :

  \longrightarrow \sf{\quad { v = u + at}} \\

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • t denotes time

Substitute the values.

  \longrightarrow \sf{\quad { v = 0 + 3(5)}} \\

  \longrightarrow \quad\underline{\boxed {\pmb{\frak{ v }} = \pmb{\frak{15 \; m \: s}}^{\pmb{\frak{-1}}}}} \\

Therefore, final velocity of the body is 15 m/s.

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Learn More :

Equations of motion :

\boxed{ \begin{array}{cc}    \pmb{\sf{ \quad \: v = u + at \quad}}  \\  \\  \pmb{\sf{ \quad \:  s= ut +  \cfrac{1}{2}a{t}^{2}  \quad \: } } \\ \\  \pmb{\sf{ \quad \:  {v}^{2} -  {u}^{2}  = 2as \quad \:}}\end{array}}

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • t denotes time
  • s denotes distance

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