a boy starting from rest runs with a uniform acceleration for 5 sec such that he covers a distance of 37.5m in 5 sec calculate the acceleration of the boy and final velocity of the body
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Answer:
a = 3 m/s²
v = 15 m/s
Explanation:
As per the provided information in the given question, we have :
- Initial velocity (u) = 0 m/s [Starts from rest]
- Time taken (t) = 5 seconds
- Distance (s) = 37.5 m
We've been asked to calculate the acceleration and the final velocity of the body.
Acceleration is defined as the rate of change in velocity. Its SI unit is m/s². It is a vector quantity. We can find the acceleration using the second equation of motion. By using the second equation of motion:
- s denotes distance
- u denotes initial velocity
- t denotes time
- a denotes acceleration
Substitute the values.
Therefore, acceleration is 3 m/s².
Now, we have to find the final velocity of the body. In order to find that so, we'll use the first equation of motion :
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- t denotes time
Substitute the values.
Therefore, final velocity of the body is 15 m/s.
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Learn More :
Equations of motion :
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- t denotes time
- s denotes distance
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