Question

A boy starting from rest travels a distance of
200m in 10s calculate the magnitude of his
acceleration.​

Answer 1

Answer:

given, u = 0, s = 200 m, t = 10 s

s = ut + 1/2 * a * t^2

200 = 0 + 1/2*a*10^2

200 = 50*a

therefore a = 200/50

= 4 m/sec^2. Answer

Answer 2

Answer :

The magnitude of acceleration is 4m/s²

Given :

• A body starts from rest travels a distance of 200m
• Time taken to travel is 10s

To Find :

• The magnitude acceleration

Formula to be used :

$\tt \star \: \: s = ut + \dfrac{1}{2}at^{2}$

Solution :

Since the body starts from rest so ,

u = 0m/s

s = 200m

t = 10s

Using the equations of motion :

$\tt 200m = 0\times 10 + \dfrac{1}{2}\times a \times 10^{2} \\\\ \tt \implies \dfrac{1}{2}\times 100 \times a = 200 \\\\ \tt\implies a = \dfrac{200}{50} \\\\ \tt \implies a = 4ms^{-2}$