Question

A boy starting from rest travels a distance of 200m in 2 sec. Calculate his acceleration ​

Answer 1

Answer:

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Answer 2

Given:-

• Initial velocity (u) = 0m/s

• Distance covered (s) = 200m

• Time (t) = 2s

To Find:-

• Acceleration of the boy (a).

Solution:-

By using 1st equation of motion

→ s = ut +1/2at²

substitute the value we get

→ 200 = 0×2 +1/2×a ×2²

→ 200 = 0 + 2×a

→ a = 200/2

→ a = 100m/s²

∴ The acceleration of the boy is 100m/s²

Additional Information!!

✧ The rate of change of velocity at per unit time is called acceleration .

✧ SI unit of acceleration is m/s²

✧ It is vector Quantity ( both magnitude and direction)