a boy starts from a point a travels to b a a distance of 3 km from a and returns to a.if he takes 2 h to do so his speed is
Answers
Answered by
1
Answer:
1.5km/h
Explanation:
SPEED IS EQUAL TO DISTANCE DIVIDED BY TIME.
Answered by
1
Answer:
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Explanation:
The movement of the person are as shown in fig.
Clearly AB = 3 km
BC=3AB=(3×3)KM=9KM
CD=5AB=(5×3)KM=15KM
Draw AE ⊥ CD.
Then CE = AB = 3 km and
AE = BC = 9Km
DE = (CD-CE)=(15-3)Km = 12 Km.
In Δ AED, AD
2
=AE
2
+DE
2
= AD=(
9
2
+(12)
2
)km=15km
∴ Required distance = AD = 15
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