A boy starts from a point, goes 10 m due east, turns towards 30° NE (North of East) and moves 20sqrt3 m, then turns to his right and moves 20m and stops. Find the resultant displacement and its magnitude.
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Explanation:
From above fig it is clear that net dispacement is AB. And AOB is a rightangked triangle with right angle at O. So to find AB, we apply pythagoras theorem,
(AB)^2=(AO)^2+(OB)^2
(AB)^2=100+400
(AB)^2=500
AB=10×2.2369
AB=22.36
So the net displacement is 22.36m
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