A boy starts from his house and travels 5 km to reach his school. On finding it closed, he returns to his house.What Is, (a) the diatance travelled by the boy. (b) The final displacement of the boy?
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a)Distance is the total length of the path travelled. Thus,the distance travelled by the boy is
d=5+5=10km
b)Displacement is the shortest length between two points it is given as
s=final position-initial position
so 5-5=0
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Concept:
Distance is the total path length while displacement is the smallest distance between two places.
Given:
Distance travelled by the boy to reach his school from home = 5km
Find:
We need to determine:
(a) The total distance travelled by the boy
(b) The final displacement of the boy
Solution:
- The whole length of the path travelled is the distance.
- It means that the distance travelled by the boy is equal to the sum of the distance travelled by the boy to reach school from home and from school to home.
- Therefore, distance = 5 + 5 = 10 km
- The smallest distance between two places is called displacement. It is denoted by the formula s = final position - beginning position.
- The boy just leaves and returns to his home during his journey. The initial and final locations are therefore identical. So, there is no displacement, s = 0
Thus, (a) the distance travelled by the boy is 10 km
(b) The final displacement of the body is zero.
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