Physics, asked by Anonymous, 1 year ago

A boy starts from his house and travels 5 km to reach his school. On finding it closed, he returns to his house.What Is, (a) the diatance travelled by the boy. (b) The final displacement of the boy?

Answers

Answered by rajammalshash
30

a)Distance is the total length of the path travelled. Thus,the distance travelled by the boy is

    d=5+5=10km

b)Displacement is the shortest length between two points it is given as

    s=final position-initial position

    so 5-5=0


Answered by soniatiwari214
0

Concept:

Distance is the total path length while displacement is the smallest distance between two places.

Given:

Distance travelled by the boy to reach his school from home = 5km

Find:

We need to determine:

(a) The total distance travelled by the boy

(b) The final displacement of the boy

Solution:

  • The whole length of the path travelled is the distance.
  • It means that the distance travelled by the boy is equal to the sum of the distance travelled by the boy to reach school from home and from school to home.
  • Therefore, distance = 5 + 5 = 10 km
  • The smallest distance between two places is called displacement. It is denoted by the formula s = final position - beginning position.
  • The boy just leaves and returns to his home during his journey. The initial and final locations are therefore identical. So, there is no displacement, s = 0

Thus, (a) the distance travelled by the boy is 10 km

(b) The final displacement of the body is zero.

#SPJ2

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