Question

A boy starts from rest and accelerates uniformly to a velocity of 6 m per second. In 15 seconds, he then decelerates uniformly to a velocity of 4 m per second in the next 5 seconds. What are the accelerations in both cases?​

Answer 1

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Answer 2

Explanation:

1-case

u=0m/s

v=6m/s

t=15sec

acceleration=v-u/t

so, acceleration=6-0/15 = 6/15 = 2/5 = 0.4m/s square

2-case

u=4m/s

v=0m/s

t=5sec

acceleration=v-u/t

so, acceleration= 0-4/5 = -4/5 = -0.8 m/s square