A boy starts from rest and moves with uniform acceleration of 5m/s2 for 8 sec
From that time acceleration ceases.find the distance covered in 12sec starting from rest
Answers
Answered by
3
Answer:
320 metres
Explanation:
Given :
- Initial velocity = u = 0 m/s
- Acceleration = a = 5 m/s²
- Time taken = t = 8 seconds
- Acceleration ceases after 8 seconds
To find :
- Distance covered in 12 seconds starting from rest
Using first equation of motion:
V=u+at
V=0+5×8
V=0+40
V=40 m/s
Now using second equation of motion :
S=ut+½at²
S=0×8+½×5×8×8
S=0+160 metres
S=160 metres
Now it travels with 40 m/s for 4 seconds
Distance travelled = 40×4
Distance travelled = 160 metres
Total distance = 160+160
Total distance = 320 metres
The total distance covered is equal to 320 metres
Answered by
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✯✯ QUESTION ✯✯
A boy starts from rest and moves with uniform acceleration of 5m/s2 for 8 sec.From that time acceleration ceases.find the distance covered in 12sec starting from rest.
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✰✰ ANSWER ✰✰
➥Using 1st Equation of Motion : -
➥Putting Values : -
➥Now ,
For Finding the distance travelled : -
➥Using 2nd Equation of Motion : -
➥Putting Values : -
➥Now ,
As the body travels 40m/s in 4 sec. For 8 seconds the distance travelled by it : -
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