a boy throw a stone with a velocity of 60 M per second what is the time it will take to come to ground
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V final velocity=0
U initial velocity=60m/s^2
G -10m/s^2(since the ball goes opposite direction to the gravity)
V=u+at
O=60-10t
t=6s
The time to reach the top is equal to the time to reach back to the ground
Hence 6s+6s =12s
U initial velocity=60m/s^2
G -10m/s^2(since the ball goes opposite direction to the gravity)
V=u+at
O=60-10t
t=6s
The time to reach the top is equal to the time to reach back to the ground
Hence 6s+6s =12s
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