Question

a boy throw ball upward. it hit the ground after t seconds,the height 'h' in meter at an time t seconds is represented by quadratic profile H(t) = t square - 5t + 6

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Answer 1

Answer:

Velocity of a ball becomes zero when the ball is at maximum height.

The interval is 2 s, which means that after the 1 st ball reaches max height at that time 2nd ball is thrown

It means time of ascent of ball is 2 s

So, time of ascent= u/g = 2

So u= 19.6 m/s

Then ,the max height= u^2/2g =19.6*19.6/2*9.8

Max height = 19.6 m

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