Physics, asked by advilraj16, 1 year ago

A boy throws a ball from shoulder height at an initial velocity of 30 m/s. Spending 4.8 sin air, the ball
is caught by another boy as the same shoulder-height level. What is the angle of projection?
(A) 37°
(B) 30°
(C) 53°
(D) 60°
AL
1​

Answers

Answered by gadakhsanket
2

Hey dear,

● Answer -

θ = 51.63°

◆ Explaination -

# Given -

u = 30 m/s

T = 4.8 s

# Solution -

Time of flight of the ball thrown in air is calculated by formula -

T = 2u.sinθ/g

4.8 = 2 × 30 × sinθ / 9.8

sinθ = (4.8×9.8) / (2 × 30)

sinθ = 0.784

θ = arcsin(0.784)

θ = 51.63°

Therefore, most appropriate answer would be 53°.

Thanks for asking...

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