Question

A boy throws a ball in air from position E.the ball hits the ground at point g.what is the maximum height achieved by ball during its trajectory

Answer 1

Answer:

H=(G-E)÷4

Step-by-step explanation:

Answer 2

 The maximum height achieved by ball during trajectory is

(E-G)/4

1. Here let us take the distance between the point E and G as EG and denote it as R and E - G = u*t.

2. Now Let the gravitational pull acting on the boy be 'g'.

3. Now we have 1/2*g*t^2=u*t.

4.Therefore t=2u/g.

5.Therefore from starting equation (E-G)*g/2=u^2

3. Now using Newton's equation of motion we get v^2=u^2+2gh.

6. Therefore H maximum = -u^2/-2g

                                          = u^2/2g

                                         =(E-G)/4