a boy throws a ball into air after 2 seconds. the next ball is thrown when velocity of first ball is zero . how do the ball rise above his hand
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the ball is at rest in 2seconds
=> time of Ascend = 2seconds
as time of Ascend=time of descend
=>total time= 2+2=4
________________________________
we know that...
total time of flight = T= √(2H/g)
=>4=√(2H/10)
=>(4)^2= 2H/10
=> 4×4×10/2=H
=> H=80m
______________________________
hope it helps u...
☺☺
=> time of Ascend = 2seconds
as time of Ascend=time of descend
=>total time= 2+2=4
________________________________
we know that...
total time of flight = T= √(2H/g)
=>4=√(2H/10)
=>(4)^2= 2H/10
=> 4×4×10/2=H
=> H=80m
______________________________
hope it helps u...
☺☺
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