Question

A boy throws a ball upwards with a velocity 20 m / s the winds imparts a horizontal acceleration of 4 m / s 2 to the left the angle theta with the vertical at which the ball should be thrown so that the ball returns to the boys hand

Answer 1

it should be thrown at angle of 90 degree

Answer 2

Answer:

Concept:

In mechanics, acceleration is the rate at which an object's velocity changes with respect to time. The term "acceleration" refers to a quantity that is measured in matrices (in that they have magnitude and direction). The orientation of the net force acting on an item determines the orientation of its acceleration. The magnitude of an object's acceleration, as described by Newton's Second Law, is the result of two factors: the net balance of all external forces acting on that object — magnitude is directly proportional to this net resulting force; and the mass of that object, which varies depending on the materials used — magnitude is inversely proportional to the mass.

Given:

A boy tosses a ball with a velocity of 20 m/s upwards, with the wind imparting a horizontal acceleration of 4 m/s 2 to the left, the angle theta with the vertical at which the ball should be thrown such that the ball returns to the boy's hand

Find:

find the answer for the given question

Answer:

The velocity difference, distance travelled over time, and net force vs mass are all used in the acceleration calculator to calculate acceleration. A positive acceleration occurs when an object accelerates and moves in a positive direction. Positive acceleration was demonstrated in the first case by the car speeding up. The car is speeding up and going forward in a positive direction, therefore the acceleration is parallel to the car's motion.

$v_{y}=v_{0}cos$θ

    $=20cos$θ

$v_{x}=v_{0}sin$θ

    $=20sin$θ

The ball's flight time is:

$T=\frac{2v_{y} }{g}$

   $=40cos$θ$/10$

   $=4cos$θ $----(1)$

The horizontal displacement of the ball should also be zero at this moment.

$0v_{x}T-\frac{1}{2} a_{x}T^{2}$

$T=\frac{2v_{x} }{a_{x} }$

   $=(20 sin$θ$)$$2/4$

   $=10sin$θ $-----(2)$

From equation (1) and (2),

$4cos$θ $=10sin$θ

$tan$θ $=\frac{4}{10}$

       $=0.4$

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