Question

A boy throws a ball upwards with a velocity of 9.8m/s.How high does it go?How long was it in the air?

Answer 1

4.8

Explanation:

v=9.8

v**2-u**2=2as

a=-10

v=0

u=9.8

Answer 2

Answer:

here,

g=-9.8m/s^2

s=?

u=9.8ms^-1

t=?

v=0

since,

v=u+at

0=9.8+(-9.8)t

9.8=9.8t

t=1second

since,

s=ut+1/2at^2

s=9.8(1)+1/2(-9.8)1×1

=4.9m

*The ball goes high to the height of 4.9m

*It was in the air for 2minutes (1 for upward and 1 for downward motion).