Question

A boy throws a ball vertically up . it returns to the ground after 5 seconds . Find
i. The maximum height reached by the ball.
ii. The velocity with which the ball is thrown up.

Answer 1

Answer:

1. 31.25 m
2. 25m/sec

Explanation:

Given :-

Time = 5sec

V = 0 (in going up)

U = 0 (in comming down)

Find :-

H and U by which it is thrown up

Since the total time is 5 sec ,therefore half time will be taken to go up and another half will be taken to go down .

We know that ,

V = U + gt

0 = U - 10*2.5

U = 25 m/sec

Also,

V² = U² +2gs

0 = 625 - 20s

s = 625/20 = 31.25 m