Question

A boy throws a ball vertically upward and catches it back in 10 seconds
(a) Calculate the velocity with which it was thrown up and
(b) Maximum height attained by ball take g is equal to 10 metre per second square.​

Answer 1

Explanation:

Catches back in 10 Sec so max height achieved in 5 sec

v = u +at

v = 0 at max height

a = -g = -9.8 (as direction upward)

0 = u + (-9.8)5

u = 49 m/s Pls mark brainliest. I beg u

Answer 2

Answer:

Explanation:

$v=ut-1/2 gt^{2}$

u=0 2t =10s implies t= 5s g=10m

v=0-5 * 25+ 625

h=u