a boy throws a ball vertically upward and catches it back in 10 seconds calculate the velocity with which it was thrown up and maximum height attained by the ball...
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Answered by
101
Catches back in 10 Sec so max height achieved in 5 sec
v = u +at
v = 0 at max height
a = -g = -9.8 (as direction upward)
0 = u + (-9.8)5
u = 49 m/s
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