Question

a boy throws a ball with an initial velocity and at such an angle of elevation, so that the range is r and maximum height to which ball rises is h find the maximum range that can be obtained with same initial velocity ​

Answer 1

Explanation:

The maximum height reached can be calculated by multiplying the time for the upward trip by the average vertical velocity. Since the object's velocity at the top is 0 m/s, the average upward velocity during the trip up is one-half the initial velocity.

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Answer 2

Explanation:

so from this,

R(max) = 2h/ sin²@

where,

@- angle of elevation.

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