Question

a boy throws a stone straight upward with an initial speed of 5 m/s from the surface of the earth. What is the maximum height above the starting point will the stone reach before it starts back?

Answer 1

Answer:

1.25m

Explanation:

u=5ms-1

v=0

g= -10(assume)

v^2=u^2-2gs

0=25- 2*10*s

25=20*s

s=5/4= 1.25m