Question

A boy throws a stone upward with a velocity of 60 m/s
1. How long will it take to reach maximum height. (take acceleration = -10m/s)
2. What is maximum height attend by the stone.
3. How long will it to reach the ground back.​

Answer 1

Explanation:

u=60m/s

at maximum height

v=0

since upward dierection let g=(-10)m/s²

maximum height

V²=U²-2gS

0=60²-2×10×S

2×10×S=3600

S=180m is the maximum height

time taken

v=u-at

0=60-10t

10t=60

t=6s, it will take 6s to reach maximum height

it takes the same time to reach down also

so 6s again to reach down