Question

a boy throws n balls per second at regular time intervals.when the first ball reaches the maximum height he throws the second one vertically up.the maximum height reached by each ball is

Answer 1

"From the given details, the value of v is 0. Then the time duration taken by every ball to reach the maximum height is 1/2s.

In this given statement, the value of n is 2. Here is procedure to calculate the height as follow:

0=u-g/2

u=g/2

0=u^2-2gh

The value of u^2 is 2gh.

g^2/4=2gh

h=g^2/8g

h=2g/8

"

Answer 2

Answer:

Explanation:

I hope it helps you