a boy Travels 30 m in 1 minute and 30 M in 1.5 minute find his average speed in m s¹
Answers
Explanation:
Total distance travelled in going and coming back
Total distance travelled in going and coming backD = 30m + 30m = 60 m
Total distance travelled in going and coming backD = 30m + 30m = 60 mTotal time taken in going and coming back
Total distance travelled in going and coming backD = 30m + 30m = 60 mTotal time taken in going and coming backt= 1 min + 1.5 min =2.5 min
Total distance travelled in going and coming backD = 30m + 30m = 60 mTotal time taken in going and coming backt= 1 min + 1.5 min =2.5 min= 2.5 60 s
Total distance travelled in going and coming backD = 30m + 30m = 60 mTotal time taken in going and coming backt= 1 min + 1.5 min =2.5 min= 2.5 60 s= 150 s
Total distance travelled in going and coming backD = 30m + 30m = 60 mTotal time taken in going and coming backt= 1 min + 1.5 min =2.5 min= 2.5 60 s= 150 sAverage speed = \frac{totaldis\tan ce\ \ travelled}{total\ time\ of\ travel}=\ \frac{60m}{150s}
Total distance travelled in going and coming backD = 30m + 30m = 60 mTotal time taken in going and coming backt= 1 min + 1.5 min =2.5 min= 2.5 60 s= 150 sAverage speed = \frac{totaldis\tan ce\ \ travelled}{total\ time\ of\ travel}=\ \frac{60m}{150s}=0.4 m\ s^{-1}