A boy travels 30 m towards North−West to point A and takes a left to travel another 70 m to point Β. At B, the boy turns left again to travel 30 m to point C. What was his
i) speed, if the total journey took him 30 min
ii) displacement
I will mark u brainliest . Please answer correctly
Answers
Explanation:
1)speed = distance / time
distance= 30+70+30=130
time=30min
speed=130/30=4.3 m/m
2)Displacement = 0
as it came back to the end point
hope this will help you
Answer :
i) 0.722222222 m/s
ii) 70m towards southwest
Explanation:
i) To find the speed firstly we have the calculate the total distance
= 30m + 70m + 30m
= 130m
Secondly, we have to convert the 30mins to second because the the total distance here is in meters.
= 30 x 60 seconds
= 1800 seconds
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So, we have to put the formula ,
=
= s = 0.722222222 m/s
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ii) Displacement = shortest path between the initial and the final position
Displacement = OC = 70meters towards southwest
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