Question

A boy travels 30 m towards North−West to point A and takes a left to travel another 70 m to point Β. At B, the boy turns left again to travel 30 m to point C. What was his
i) speed, if the total journey took him 30 min
ii) displacement
I will mark u brainliest . Please answer correctly

Answer 1

Explanation:

1)speed = distance / time

distance= 30+70+30=130

time=30min

speed=130/30=4.3 m/m

2)Displacement = 0

as it came back to the end point

hope this will help you

Answer 2

Answer :

i) 0.722222222 m/s

ii) 70m towards southwest

Explanation:

i) To find the speed firstly we have the calculate the total distance

= 30m + 70m + 30m

= 130m

Secondly, we have to convert the 30mins to second because the the total distance here is in meters.

= 30 x 60 seconds

= 1800 seconds

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So, we have to put the formula $s=\frac{d}{t}$,

= $s=\frac{70}{1800}$

= s = 0.722222222 m/s

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ii) Displacement = shortest path between the initial and the final position

Displacement = OC = 70meters towards southwest

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Rudra, please mark it as Brainliest.

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