Question

A boy travels along the path ABCD as shown in the figure above. Find the distance and displacement.

answer plz ​

Answer 1

Answer:

Distance= AB+BC+CD= 4+4+10=18cm

Displacement= √[(4^2)+(6^2)]=7.21cm

Answer 2

Explanation:

distance =4+4+10=18

displacement=10-8=2

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