A boy travels from home to market and returns back to the home in 3 hours. if the market is at a distance of 5 km from home, the distance travelled by the boy is
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Answer:
agar market jaa Raha hai aur market 5km ki distance me hai tho wo BHo tho 5km hi travel karega
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Answer:
Average speed =totaltimetotaldistance
Time taken to go to the market =speeddistance=52.5hour=21hours=30 minutes
Time taken to return back =speeddistance=7.52.5hour=1/3hours=20 minutes
Distance travelled in 10 minutes while returning back=6010×7.5=1.25km ( Speed is constant at 7.5 km/hr )
Hence Distance traveled in 40 minutes(30 mins towards the market and 10 mins towards home) =2.5+1.25=3.75km
So average speed in 0 to 40 minutes =6040hr3.75km
=845 km/hr
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