Physics, asked by samirkhan9133, 9 months ago

A BOY UNDER 10KM EAST IN 2 HRS AND THEN 2.5 KM WEST IN 1 HR. CALCULATE THE TOTAL AVERAGE VELOCITY OF THIS BOY

Answers

Answered by Anonymous
35

Answer:

2.5 km/hr

Explanation:

Given:

Displacement towards east = 10 km

Time for travelling 10 km towards east = 2 hrs

Displacement towards west = 2.5 km

Time for travelling 2.5 km west = 1 hour

To find:

Average velocity of the body

Average\ velocity=\frac{total\ displacement}{total\ time}

As the boy is travelling towards east and then west , the distance travelled towards west should be subtracted from the distance travelled towards east

Total displacement = 10km-2.5km

Total displacement = 7.5 km

Total time = 1 hour+2hours

Total time = 3 hours

average\ velocity=\frac{7.5}{3}

average\ velocity = 2.5 km/hr

The average velocity is equal to 2.5 km/hr

Answered by Anonymous
48

Answer:

\bigstar\:\boxed{\sf Average\: Velocity=\dfrac{Total\: Displacement}{Total\:Time}}

\rule{120}{1}

  • Boy travelled 10km East in 2 hours & Then 2.5km West in 1 hour.
  • As Boy Returned towards East, therefore according to Definition : Distance from Starting Point to End Point is Displacement.

\underline{\bigstar\:\textbf{According to the Question :}}

:\implies\sf Average\: Velocity=\dfrac{Total\: Displacement}{Total\:Time}\\\\\\:\implies\sf Average\: Velocity=\dfrac{10-2.5}{2+1}\\\\\\:\implies\sf Average\: Velocity=\dfrac{7.5}{3}\\\\\\:\implies\underline{\boxed{\sf Average\: Velocity=2.5\:km/hr}}

\therefore\:\underline{\textsf{Average Velocity of Boy will be \textbf{2.5 km/hr}}}.

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