Question

a boy walk 8 m towards north then 6 m forwards east calculate the distance and displacement of the boy​

Answer 1

Answer:

A man walks 8m towards East and then 6m towards North

Using pythagoras theorem P  

2

=8  

2

+6  

2

=100

P=10m displacement is 10m

or

Step 1: Displacement Vector [Ref Fig.1]  

Displacement of the man is given by

                 

S

=8  

i

^

+6  

j

^

​

m

Step 2: Resultant calculation [Ref. Fig. 2]

                ∣  

S

∣=  

x  

2

+y  

2

 

​

 

                      =  

8  

2

+6  

2

 

​

=10m

                ∣  

S

∣=10m

Hence magnitude of displacement is 10m