A boy walked 2 Km towards North and then 3 Km towards West and then 1 Km South and then 3 Km East. How far the boy from starting point? a) 2 Km b) 8 Km c) 4 Km d) 3 Km
Answers
Answer:
1 km
Step-by-step explanation:
Options are not correct
Starting point P.
1st travelling towards North
from point P to A=S1= 3 km
2nd travelling towards West
from A to B = S2= 2 km
3rd travelling towards North
from B to C = S3= 1 km
4th travelling towards East
from C to E1 =S4= 5 km
Joining all these points, finally we get a triangle from starting point P to the final destination E1 after covering a distance of 5 km to the East. The position of the traveller is now point E1, North-East (NE) position which is a diagonal measurement of the trianglar path from starting point P to E1.
Starting point P to North-East position E1:
Distance covered =d2= S1 + S3
d2 = 3 km + 1 km = 4 km
Length of triangluar side from West to East DE1:
d1 = DE1= S4 - S2 = 5 - 2 = 3 km
Using Pythagorean’s theorem:
d1^2 + d2^2 = PE1^2
4^2 + 3^2 = PE1^2
PE1^2 = 16 + 9 = 25
PE1 = 5 km
upper ☝️ are are answer and this is written
answer=The traveller is at a distance PE1 = 5 km from starting point to the end point E1 in the North-East direction.