Question

A boy walking along the three sides of a equilateral triangle at the speeds of 6km/hr, 3km/r and x km/r and the average speed of the boy around the field is 24/5 km/hr. Find x?

Answer 1

Answer:

What price should a trader mark on a article that costs him rupees 4000 to gain 10% after allowing a discount of 12 %

Step-by-step explanation:

Answer 2

The value of "x is 8".

Step-by-step explanation:

We know that, if three equal distances are covered at different speeds of A, B and C km/h respectively,

Average speed during whole journey = $\dfrac{3ABC}{AB + BC + CA}$

Given,

A = 6 $\dfrac{km}{hr}$, B = 3 $\dfrac{km}{hr}$ and

A = x $\dfrac{km}{hr}$ = ?

∴  $\dfrac{3ABC}{AB + BC + CA}$ = $\dfrac{24}{5}$

⇒ $\dfrac{3(6)(3)(x)}{(6)(3) +(3)(x) + (x)(6)}$ = $\dfrac{24}{5}$

⇒ $\dfrac{54x}{(18 + 3x + 6x}$ = $\dfrac{24}{5}$

⇒ $\dfrac{54x}{(18 + 9x}$ = $\dfrac{24}{5}$

⇒ 270x = 432 + 216x

⇒ 270x - 216x = 432

⇒ 54x = 432

⇒ x = 8

Hence, the value of x is 8.