Question

A boy walks 10m at an angle 30degree north of east .how for east and how for north has he travelled

Answer 1

$\color{red}\huge{\underline{\underline{GIVEN\dag}}}$

• A boy walks 10m towards north of east at an angle 30°

$\color{red}\huge{\underline{\underline{SOLUTION\dag}}}$

We know that;

How far he have traveled east is "x"

similarly "y" represents how he traveled along north.

But;

$\sin(30) = \frac{y}{10}$

$\implies \frac{1}{2} \times 10 = y$

$\color{orange}\therefore y = 5m$

Similarly;

$\cos(30) = \frac{x}{10}$

$\frac{ \sqrt{3} }{2} \times 10 = x$

$\color{orange} \therefore x = 5 \sqrt{3}$

THEREFORE,

he have traveled $5m$along north.

and $5\sqrt{3}m$ along east.

HOPE THAT HELPS!!