Question

a boy walks 12m due east and 5m due south . how far is he from the starting point

Answer 1

12² + 5² = 144 + 25
= 169= 13²
starting point = 13m
note : use Pythagoras theorem

Answer 2

Concept:

The Pythagoras Theorem: The Pythagoras Theorem states that the sum of squares of the base of the triangle and perpendicular of the triangle is equal to the square of the hypotenuse of the triangle.

It is applicable in a right angled triangle.

A right angled triangle is the one in which one of the interior angles is 90°.

Given:

We are given that a boy walks 12m due east and 5m due south .

Find:

We need to find his distance from the starting point.

Solution:

We will do this by applying the Pythagoras theorem.

Distance (D) will be:

D²=12²+5²

D²=144+25

D²=169

D=13 m.

Therefore, the distance from the starting point of the boy is 13 m.

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