Question

.A boy walks a distance of 5m in 8 seconds and the next 12m in 15 seconds. is he walking with uniform speed.​

Answer 1

Answer:

he is walking in AD direction

Explanation:

REF.Image.

Distance covered in 25=v.t=10m v=5m/s

85=v.t=40m

His path :

Taking A are origin

A≡(0,.0)

D=(−30,−40)

(t=

v

d

=

5

40

=8s)

(1)Displacement =d(AD)=

40

2

+30

2

=

1600+900

=

2500

=

50m

(ii) Total distance =10+40+40=

90m

(iii) Avg. speed =

TotalTime

TotalDistance

=

2+8+8

90m

=

18

90

=

5m/s

(iv)Avg. velocity =

Totaltime

TotalDisplacement

=

18

50

=

2.78m/s

in

AD

direction

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Answer 2

Answer:

27.8

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