Question

a boy walks on a corridor 10m from east to west what is the displacement and distance travelled ?

Answer 1

AF = AB – BF = AB – DE = 50 – 20 = 30 m His displacement is AD AD = √(AF^2-DF^2 ) = √(〖30〗^2+〖40〗^2 ) = 50m In ∆AED tan θ = DE/AE = 30/40 = ¾ ⇒ θ = tan-1 (3/4) His displacement from his house to the field is 50 m, tan-1 (3/4) north to east.