A boy walks to a picnic spot from his house in 6hours, but he can travel the same distance on his cycle in 2 hours. if his average cycling speed is 7kp per hour faster than his average walking speed, find his avg cycling speed and avg walking speed?
Answers
Answered by
30
Speed = 6 km/h
Distance = x km
Time = Distance/Speed
= (x/6) hrs.
Case 2
Speed = 2 km/h
Distance = x km
Time = Distance/Speed
= (x/2) hrs.
Now, Total Distance covered by boy = 2x km
Total Time taken = x/6 + x/2
= (x + 3x)/6
= 4x/6
= (2x/3) hrs.
Avreage speed of boy = Total Distance covered / Total Time taken
= 2x/2x/3
= 2x * 3/2x
= 3 km/h
atharva88:
nice bro
Answered by
10
Answer:
Step-by-step explanation:Speed = 6 km/h
Distance = x km
Time = Distance/Speed
= (x/6) hrs.
Case 2
Speed = 2 km/h
Distance = x km
Time = Distance/Speed
= (x/2) hrs.
Now, Total Distance covered by boy = 2x km
Total Time taken = x/6 + x/2
= (x + 3x)/6
= 4x/6
= (2x/3) hrs.
Avreage speed of boy = Total Distance covered / Total Time taken
= 2x/2x/3
Solve...
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