a boy walks to his school at a distance of 6km with a speed of 2.5km/hr and walks back with a constant speed of 5km/hr. His average speed for round trip expressed in km/hr is?
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Answered by
2
average speed =
total distance travelled/total time taken
total distance =6+6=12km
time to school
time =6/2.5=2.4 s
time to home
time!=6/4=1.5 s
total time = 3.9 s
average speed = 12/3.9=3.076 km/s
=3076m/s approx
total distance travelled/total time taken
total distance =6+6=12km
time to school
time =6/2.5=2.4 s
time to home
time!=6/4=1.5 s
total time = 3.9 s
average speed = 12/3.9=3.076 km/s
=3076m/s approx
Answered by
2
This question is very simple.
Average speed = Total Distance / Total Time Taken
We have given speeds S1 and S2
S1 = 2.5 km/hr
S2 = 5 km/hr
And Distance D1 and D2
D1 = 6 km
D2 = 6 km
Total Distance = D1 + D2 = 6 + 6 = 12 km
Now
T1 = D1/S1
T1 = 6/2.5 = 2.4 hr
T2 = D2/S2
T2 = 6/5 = 1.2 hr
Total Time = T1 + T2 = 2.4 + 1.2 = 3.6 hr
Now
Average Speed = Total Distance / Total Time = 12 / 3.6
Average Speed = 3.33 km/hr
i hope it will helpful for
@sushany❤❤
Average speed = Total Distance / Total Time Taken
We have given speeds S1 and S2
S1 = 2.5 km/hr
S2 = 5 km/hr
And Distance D1 and D2
D1 = 6 km
D2 = 6 km
Total Distance = D1 + D2 = 6 + 6 = 12 km
Now
T1 = D1/S1
T1 = 6/2.5 = 2.4 hr
T2 = D2/S2
T2 = 6/5 = 1.2 hr
Total Time = T1 + T2 = 2.4 + 1.2 = 3.6 hr
Now
Average Speed = Total Distance / Total Time = 12 / 3.6
Average Speed = 3.33 km/hr
i hope it will helpful for
@sushany❤❤
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