Question

A boy walks to his school with a constant speed of 4 km/h and reaches there in
30 minutes. Find the distance of the school from his house.​

Answer 1

Answer:

we know

speed = distance/time

hence

$(4 \times 1000) \div 60$we converted the speed into m/min

now

66.67= distance/ 30

hence distance = 2000 meters

(you can convert it into km if needed)

Answer 2

Explanation:

Initial velocity(u)of boy= 4km/h

=4×1000/3600

=4000/3600

=1.11m/s

Final velocity(v) =0 (finally the boy stops)

Time taken(t)=30minutes

=30×60=1800 seconds

According to first equation of motion

V=U+AT

0=1.11+A×1800

0=1.11+1800A

A=V - U/T

A=0 - 1.11/1800

A=0.00061

NOW ACCORDING TO SECOND EQUATION OF MOTION

S=UT+1/2AT^2

S=1.11×1800+1/2×0.00061×1800

S=1998+0.549

S=1998.549 metre

So, the distance of the school from his house is 1998.549m.