A boy wants to throw a paper wrapped over a stone to his friend across the street 40m wide.the boy window is 10m below the friend window .how should he throw the ball?
Answers
Answered by
27
Hello Dear,
◆ Answer -
The boy should throw the stone at 31.3 m/s at angle of 26.57° with horizontal.
◆ Explanation -
This can be illustrated as projectile motion of the stone.
For successful throwing of the stone in friend's window,
- Horizontal range should be double that of 40 m. i.e. R = 80 m
- Maximum height need to be 10 m. i.e. H = 10 m
Now we have to calculate angle of projection,
tanθ = 4H/R
tanθ = 4 × 10 / 80
tanθ = 1/2
θ = arctan(1/2)
θ = 26.57°
To calculate initial velocity, we'll use formula -
R = u².sin2θ/g
80 = u² × sin(2×26.57) / 9.8
u² = 80 × 9.8 / 0.8
u² = 980
u = 31.3
u = 31.3 m/s
Thus, boy should throw the stone at 31.3 m/s at angle of 26.57° with horizontal.
Thanks dear...
Similar questions