Question

A boy weighing 60 kgf is wearing shoes with heels of area of cross section 20 cm square, while a girl weighing 45 kgf is wearing sandals with heels of area of cross section 1.5 cm square.Compare the pressure exerted on the ground by their heels when they stand on the heel ofone foot. perfect answer with process will be marked as brainlist answer quickly solve it please ​

Answer 1

Explanation:

Given,

mass of boy = 60 kg

area of his shoes = 20 CM i.e. 0.2 m

pressure exerted by boy = force / area

= mass ^ acceleration / area

= 60^ 10 (a due to earth) /0.1 ( area of one foot)

= 6000 Pascal

Now,

mass of girl = 45 kg

area of her sandals = 1.5 CM =0.0075 (area of one foot)

p = f /a

= ma/area

= 45 ^ 10 /0.0075

= 60000 Pascals

hence the pressure exerted is 10 times greater in case of girl than boy.

Answer 2

it ten times greater the boy